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Mac Forum / Programming / Mac Programming / February 2008x86_64 assembler "movb" instruction
The as assembler accept "movb %al,0(%rsi)" but not "movb %r8,0(%rsi)" (invalid r8 register...) Why ? How to put (least significative) byte in r8 to memory 0(%rsi) ? (with a single instruction...) > The as assembler accept "movb %al,0(%rsi)" > but not "movb %r8,0(%rsi)" (invalid r8 register...) > > Why ? > > How to put (least significative) byte in r8 to memory 0(%rsi) ? (with a single instruction...) Solved: add b suffix to register name movb %r8d,0(%rsi) It is a little bit redundant... mov %r8d,0(%rsi) is also valid. |
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